编排(迭代41)＋闸交叉核语义扩展: 卡②核心数据面结构收敛批(≈7.9d)→卡③呈现层结构收敛批(≈5.3d)编入迭代41,合计≈13.15个工作日〔用户特批 2026-10-27 超 10 个工作日〕——三迭代/两迭代+特批两案用户裁后案;卡序=执行顺序;待办条目状态推进已编迭代41;闸修订=交叉核从「条目单迭代号×单卡路径」扩展为「每已编迭代段×条目卡集any覆盖」(check_status返回已编迭代号列表/links按段展开/cross_check按行核条目至少一卡)——一条目多卡分编多迭代是本次编排的真实形态,旧模型单值取末段漏核40段且41段误比40行卡;卡级映射(哪张卡编哪个迭代)仍归编排四查与人工,闸只防引用断裂;pipeline_gate绿(52条目/41行/4链/12卡)
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@@ -74,6 +74,7 @@
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| 迭代 38 | 已完成（2026-10-26） | 已退役（git 历史可考） | 2026-10-26 | ≈5.225 个工作日 | 已退役（git 历史可考） |
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| 迭代 39 | 待开工 | reports/需求卡片-冒险域拆件与账本实体化批-2026-10-26.md<br>reports/需求卡片-同调配装充能域封装批-2026-10-26.md<br>reports/需求卡片-技能池情境条件触发器批-2026-10-26.md | 2026-10-26 | ≈10.15 个工作日〔用户特批 2026-10-26 超 10 个工作日〕 | — |
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| 迭代 40 | 待开工 | reports/需求卡片-B1战斗域拆件批-2026-10-27.md<br>reports/需求卡片-结构小件定点修批-2026-10-26.md | 2026-10-27 | ≈6.225 个工作日 | — |
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| 迭代 41 | 待开工 | reports/需求卡片-核心数据面结构收敛批-2026-10-27.md<br>reports/需求卡片-呈现层结构收敛批-2026-10-27.md | 2026-10-27 | ≈13.15 个工作日〔用户特批 2026-10-27 超 10 个工作日〕 | — |
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- 迭代 38 收口为带红合并〔用户特批 2026-10-26〕：09 静态扫描 S13 gdstyle 恶化 2 条经批准记入基线存量红（git 提交 c4c69701），卡② 停卡退上游，处方已于 2026-10-26 修订定稿 v1.3（git 提交 b3ea7532），随「gdstyle 存量债全量清偿」条目波 7 待编排。
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- 历史行的「—」= 该列事实不可考：迭代 1~8 早于需求卡片制；编排时点与预计周期不再回溯，细节查 git 提交史。
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+19
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@@ -148,7 +148,7 @@ def check_segment(word, line, issues, where):
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def check_status(raw, line, issues, where):
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"""判据 3＋状态段累积制（§12.1）＋特批/备选。返回 (状态词列表, 已编迭代号|None)。
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"""判据 3＋状态段累积制（§12.1）＋特批/备选。返回 (状态词列表, 已编迭代号列表|[])。
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累积制：按＋切段后段数不限，逐段各自合法；再查一条结构约束——下游段
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（待写卡/已写卡/已编迭代）在场时禁残留未闭合设计段（带日期特批可豁免）。
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@@ -177,13 +177,13 @@ def check_status(raw, line, issues, where):
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if not segs:
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issues.append((where, line, "状态词非法", "状态行内容为空"))
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return [], None
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words, iter_no = [], None
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words, iter_nos = [], []
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for seg in segs:
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w, it = check_segment(seg, line, issues, where)
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if w:
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words.append(w)
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if it is not None:
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iter_no = it
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iter_nos.append(it)
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# 同一设计线只留最新一段：并现两段说明推进时忘了收旧段，或把另一条线的段
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# 误写进本线条目；跨条设计线的未闭合依赖（如文档线已闭合写卡、美术线仍待设计）合法。
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for track, name in ((DOC_DESIGN_WORDS, "文档线"), (ART_DESIGN_WORDS, "美术线")):
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@@ -191,7 +191,7 @@ def check_status(raw, line, issues, where):
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if len(hit) > 1:
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issues.append((where, line, "设计线段并现",
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"%s同时出现 %s（同线只留最新一段，§12.1）" % (name, "、".join(hit))))
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return words, iter_no
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return words, iter_nos
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def check_todo(text, issues, where, root):
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@@ -228,7 +228,7 @@ def check_todo(text, issues, where, root):
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issues.append((where, line, "属性缺失", "条目缺「**%s**」属性" % req))
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if "状态" not in attrs:
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continue
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words, iter_no = check_status(attrs["状态"], attr_line["状态"], issues, where)
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words, iter_nos = check_status(attrs["状态"], attr_line["状态"], issues, where)
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# 改动面：四档取多，＋连接，禁重复、禁自造词
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if "改动面" in attrs:
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parts = [p.strip() for p in SURFACE_SEP_RE.split(attrs["改动面"]) if p.strip()]
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@@ -297,8 +297,9 @@ def check_todo(text, issues, where, root):
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if not need_gap and words and "缺口" in attrs:
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issues.append((where, line, "缺口属性",
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"状态为 %s，设计已闭合/后段不得残留「**缺口**」属性" % "、".join(words)))
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if iter_no is not None:
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links.append((line, iter_no, cards[0] if cards else None))
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if iter_nos:
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for no in iter_nos:
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links.append((line, no, cards))
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return links
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@@ -423,17 +424,23 @@ def check_roadmap(text, issues, where, root):
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def cross_check(links, index, issues, where):
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"""唯一一处交叉核：已编迭代 N ↔ 总表迭代 N 行的需求卡片列。"""
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for line, no, card in links:
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"""唯一一处交叉核：已编迭代 N ↔ 总表迭代 N 行的需求卡片列。
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一条目可有多张已写卡分编多个迭代（状态段累积「已编迭代 40＋已编迭代 41」）：
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对每个已编迭代号核两件——总表该行存在；该行卡片列含本条目至少一张已写卡路径。
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哪张卡编哪个迭代的卡级映射由编排四查与人工核验，闸不猜卡级映射。
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"""
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for line, no, cards in links:
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row = index.get(no)
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if row is None:
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issues.append((where, line, "交叉核", "迭代总表无迭代 %d 行" % no))
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elif card is None:
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elif not cards:
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issues.append((where, line, "交叉核",
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"已编迭代 %d 但条目无可引的已写卡路径（须先已写卡）" % no))
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elif card not in row[1]:
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elif not any(c in row[1] for c in cards):
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issues.append((where, line, "交叉核",
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"迭代 %d 行卡片列不含本条目已写卡路径 %s" % (no, card)))
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"迭代 %d 行卡片列不含本条目任何已写卡路径（%s）"
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% (no, "／".join(cards[:3]))))
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def card_date(path):
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